Charles S. Peirce

Writings of Charles S. Peirce: A Chronological Edition, Volume 2


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      So

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      But

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      Let Image be the sign of logical subtraction; so defined that

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      Here it will be observed that x is not completely determinate. It may vary from a to a with b taken away. This minimum may be denoted by a —b. It is also to be observed that if the sphere of b reaches at all beyond a, the expression Image is uninterpretable. If then we denote the contradictory negative of a class by the letter which denotes the class itself, with a line above it,1 if we denote by v a wholly indeterminate class, and if we allow Image to be a wholly uninterpretable symbol, we have

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      which is uninterpretable unless

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      If we define zero by the following identities, in which x may be any class whatever,

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      then, zero denotes the class which does not go beyond any class, that is nothing or nonentity.

      Let a ; b be read a logically divided by b, and be defined by the condition that

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      x is not fully determined by this condition. It will vary from a to Image and will be uninterpretable if a is not wholly contained under b. Hence, allowing [1;0] to be some uninterpretable symbol,

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      which is uninterpretable unless

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      Unity may be defined by the following identities in which x may be any class whatever.

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      Then unity denotes the class of which any class is a part; that is, what is or ens.

      It is plain that if for the moment we allow a : b to denote the maximum value of a ; b, then

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      So that

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      The rules for the transformation of expressions involving logical subtraction and division would be very complicated. The following method is, therefore, resorted to.

      It is plain that any operations consisting solely of logical addition and multiplication, being performed upon interpretable symbols, can result in nothing uninterpretable. Hence, if φ + × x signifies such an operation performed upon symbols of which x is one, we have

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      where a and b are interpretable.

      It is plain, also, that all four operations being performed in any way upon any symbols, will, in general, give a result of which one term is interpretable and another not; although either of these terms may disappear. We have then

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      We have seen that if either of these coefficients i and j is uninterpretable, the other factor of the same term is nothing, or else the whole expression is uninterpretable. But

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      Hence

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      Developing by (18) Image, we have,

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      So that, by (11),

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      Developing x; y in the same way, we have2

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      So that, by (14),

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      Boole gives (20), but not (19).

      In solving identities we must remember that

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      From Image the value of b cannot be obtained.

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      From a ; b the value of b cannot be determined.

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      Required to eliminate x.

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      Logically multiplying these identities, we get

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      For two terms disappear because of (17).

      But we have, by (18),

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      Multiplying logically by x we get

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      Substituting these values above, we have

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      Required to eliminate x.

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      Now, developing as in (18), only in reference to φ(1) and φ(0) instead of to x and y,

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      But by (18) we have also,