Claude Cohen-Tannoudji

Quantum Mechanics, Volume 3


Скачать книгу

for the spatial range of the wave function transition regime. In the region where φ(r) is constant, relation (56) yields:

      (58)image

      On the other hand, in the whole region where φ(r) has significantly decreased, and in particular close to the origin, we have:

      (59)image

      (60)image

      whose solutions are sums of exponential functions e±ix/ξ, with:

      The stronger the interactions, the shorter this “healing length” ξ; it varies as the inverse of the square root of the product of the coupling constant g and the density n0. From a physical point of view, the healing length results from a compromise between the repulsive interaction forces, which try to keep the wave function as constant as possible in space, and the kinetic energy, which tends to minimize its spatial derivative (while the wave function is forced to be zero at x = 0); ξ is equal (except for a 2π coefficient) to the de Broglie wavelength of a free particle having a kinetic energy comparable to the repulsion energy gn0 in the boson system.

      We now show that repulsive interactions do stabilize a boson “condensate” where all the particles occupy the same individual state, as opposed to a “fragmented” state where some particles occupy a different state, which can be very close in energy. Instead of using a trial ket (7), where all the particles form a perfect Bose-Einstein condensate in a single quantum state |θ〉, we can “fragment” this condensate by distributing the N particles in two distinct individual states. Consequently, we take a trial ket where Na particles are in the state |θa〉 and Nb = NNa in the orthogonal state |θb〉:

      (62)image

      (63)image

      The computation of the one-body potential energy is similar and leads to:

      (64)image

      In both cases, the contributions of two populated states are proportional to their respective populations, as expected for energies involving a single particle.

       - k = l = m = n = a or b yields the contribution:(65)

       - k = m = a and l = n = b, or k = m = b and l = n = a; these two possibilities yield the same contribution (since the W2 operator is symmetric), and the 1/2 factor disappears, leading to the direct term:(66)

       - Finally k = n = a and l = m = b, or k = n = b and l = m = a, yield two contributions whose sum introduces the exchange term (here again without the factor 1/2):

      (67)image

      The direct and exchange terms have been schematized in Figure 3 in Chapter XV (replacing |ui〉 by |θa〉, and |uj〉 by |θb〉), with the direct term on the left, and the exchange term on the right.

      (68)image

      As above, the interaction between particles in the same state |θa〉 contributes a term proportional to Na (Na — 1)/2, the number of pairs of particles in that state; the same is true for the interaction term between particles in the same state |θb〉. The direct term associated with the interaction between two particles in distinct states is proportional to NaNb, the number of such pairs. But to this direct term we must add an exchange term, also proportional to NaNb, corresponding to an additional interaction. This increased interaction is due to the bunching effect of two bosons in different quantum states, that will be discussed in more detail in § 3-b of Complement AXVI. As they are indistinguishable, two bosons occupying individual orthogonal states show correlations in their positions; this increases the probability of finding them at the same point in space. This increase does not occur when the two bosons occupy the same individual quantum state.

      We now assume the diagonal matrix elements of [K0 + V1] between the two states |θa〉 and |θb〉 to be practically the same. For example, if these two states are the lowest energy levels of spinless particles in a cubic box of edge L, the corresponding energy difference is proportional to 1/L2