William M. White

Geochemistry


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to which these enthalpies apply. These conditions, by convention, are 298.15 K and 0.1 MPa (25°C and 1 bar). Under these conditions the elements are assigned enthalpies of 0. Standard state enthalpy of formation, or heat of formation, from the elements, ΔH°, can then be determined for compounds by measuring the heat evolved in the reactions that form them from the elements (e.g., Example 2.2). For example, the heat of formation of water is determined from the energy released at constant pressure in the reaction: H2 + ½O2 → H2O, which yields a ΔH° of −285.83 kJ/mol, where water is in the liquid state. The minus sign indicates heat is liberated in the reaction, that is, the reaction is exothermic (a reaction that consumes heat is said to be endothermic).

      Having established such a system, the enthalpy associated with a chemical reaction is easily calculated using Hess's law, which is:

      (2.115)equation

      The heat of vaporization of a substance is the energy required to convert that substance from liquid to gas, i.e., to boil it. If the reaction H2 + ½O2 → H2O is run to produce water vapor, the ΔH° turns out to be −241.81 kJ/mol. The difference between the enthalpy of formation of water and vapor, 44.02 kJ/mol, is the heat consumed in going from liquid water to water vapor. This is exactly the amount of energy that would be required to boil 1 mole of water. Analogously, the heat of melting (or fusion) is the enthalpy change in the melting of a substance. Because reaction rates are often very slow, and some compounds are not stable at 298 K and 1 MPa, it is not possible to measure the enthalpy for every compound. However, the enthalpies of formation for these compounds can generally be calculated indirectly.

      What is the energy consumed or evolved in the hydration of corundum (Al2O3) to form gibbsite (Al(OH)3)? The reaction is:

equation

      Answer: We use Hess's law. To use Hess's law, we need the standard state enthalpies for water, corundum, and gibbsite. These are: Al2O3: −1675.70 kJ/mol, H2O: −285.83 and Al(OH)3: −1293.13. The enthalpy of reaction is images.

      This is the enthalpy of reaction at 1 bar and 298 K. Suppose you were interested in this reaction under metamorphic conditions such as 300°C and 50 MPa. How would you calculate the enthalpy of reaction then?

      2.10.3 Entropies of reaction

      Since

      (2.62)equation

      and

      (2.57)equation

      then at constant pressure

      (2.116)equation

      Thus, at constant pressure, the entropy change in a reversible reaction is simply the ratio of enthalpy change to temperature.

      Entropies are additive properties and entropies of reaction can be calculated in the same manner as for enthalpies, so Hess's law applies:

      (2.118)equation

Phase/ Compound Formula images kJ/mol SO J/K-mol images kJ/mol images cc/mol* a CP b c
H2Og H2O (gas) −241.81 188.74 −228.57 24789.00 30.54 0.01029 0
H2Ol H2O (liquid) −285.84 69.92 −237.18 18.10 29.75 0.03448 0
CO2 CO2 −393.51 213.64 −394.39 24465.10 44.22 0.00879 861904
Calcite CaCO3 −1207.30 92.68 −1130.10 36.93 104.52 0.02192 2594080
Graphite C 0 5.740 5.298
Diamond C 1.86 2.37 3.417
Aragonite CaCO3 −1207.21 90.21 −1129.16