J is isomorphic to one of the superalgebras in examples 1.8, 1.9 and 1.10–1.15 or it is the Kantor double of the Poisson bracket in example 1.17.
REMARK 1.3.– We will assume always in this section that
1.6.2. Case char F = p > 2, the even part
Let us assume next that char F = p > 2 and the even part
Recall that a semisimple Jordan algebra is a direct sum of finitely many simple ideals.
This case was addressed in Racine and Zelmanov (2003) and the classification essentially coincides with the one of zero characteristic, expect of some differences if char F = 3.
EXAMPLE 1.21.– Let H3(F), K3(F) denote the symmetric and skew-symmetric 3×3 matrices over F, char F = 3. Consider
via a ∙ b = a ∙ b in M3(F)+ if a, b ∈ H3(F), that is,This superalgebra is simple.
EXAMPLE 1.22.– Let
The action of
Shestakov (1997) proved that B is an alternative superalgebra and has a natural involution ∗ given by (a + m)∗ = ā – m,
If H3(B, ∗) denotes the symmetric matrices with respect to the involution ∗, then H3(B, ∗) is a simple Jordan superalgebra. It is i-exceptional, that is, it is not a homomorphic image of a special Jordan superalgebra.
THEOREM 1.2 (Racine and Zelmanov (2003)).– Let
be a finite dimensional central simple Jordan superalgebra over an algebraically closed field F of char F = p > 2. If 1.6.3. Case char F = p > 2, the even part
This case shows similarities with infinite dimensional superconformal Jordan algebras (see section 1.8) in characteristic 0.
Let us denote
THEOREM 1.3 (Martínez and Zelmanov (2010)).– Let
be a finite dimensional simple unital Jordan superalgebra over an algebraically closed field F of characteristic p > 2. If the even part1.6.4. Non-unital simple Jordan superalgebras
Finally, let us consider non-unital simple Jordan superalgebras. As we have seen, K3 the three-dimensional Kaplansky superalgebra and K9 the nine-dimensional degenerate Kac superalgebra are examples of such superalgebras.
EXAMPLE 1.23.– Let Z be a unital associative commutative algebra, D : Z → Z a derivation. Assume that Z is D-simple and that the only constants are elements α1, α ∈ F.
Let us consider in Z the bracket { , } given by:
The above bracket is a Jordan bracket, so the Kantor double V(Z, D) = Z + Zv = KJ(Z, { , }) is a simple