William M. White

Geochemistry


Скачать книгу

Fe3+ + e ⇌ Fe2+ 0.77 13.02 NO3+ + 2H+ + e ⇌ NO2(g) + H2O 0.80 13.53 Ag+ + e ⇌ Ag 0.80 13.53 Hg2+ + 2e ⇌ Hg 0.85 14.37 MnO2(s) + 4H+ + 2e ⇌ Mn2+ + 2H2O 1.22 20.63 O2 + 4H+ + 4e ⇌ 2H2O 1.23 20.80 MnO4– + 8H+ + 5e ⇌ Mn2+ + 4H2O 1.51 25.53 Au+ + e ⇌ Au 1.69 28.58 Ce4+ + e ⇌ Ce3+ 1.72 29.05 Pt+ + e ⇌ Pt 2.64 44.64

      * CH2O refers to carbohydrate, the basic product of photosynthesis.

      The half-cell reactions in Table 3.3 are arranged in order of increasing images. Thus, a species on the product (right) side of a given reaction will reduce (give up electrons to) the species on the reactant side in all reactions listed below it. Thus, in the Daniell cell reaction in Figure 3.18, Zn metal will reduce Cu2+ in solution. Zn may thus be said to be a stronger reducing agent than Cu.

      Electrochemical energy is another form of free energy and can be related to the Gibbs free energy of reaction as:

      and

      where z is the number of electrons per mole exchanged (e.g., 2 in the reduction of zinc) and images is the Faraday constant (images = 96,485 coulombs; 1 joule = 1 volt-coulomb). The free energy of formation of a pure element is 0 (by convention). Thus, the ΔG in a reaction that is opposite one such as 3.105, such as:

equation

      is the free energy of formation of the ion from the pure element. From eqn. 3.106 we can calculate the ΔG for the reduction of zinc as 147.24 kJ/mol. The free energy of formation of Zn2+ would be −147.24 kJ/mol. Given the free energy of formation of an ion, we can also use eqn. 3.105 to calculate the hydrogen scale potential. Since

      we can substitute eqns. 3.106 and 3.107 into 3.108 and also write

      (3.110)equation

      We can deduce the meaning of this relationship from the relationship between ΔG and E in eqn. 3.106. At equilibrium ΔG is zero. Thus, in eqn. 3.108, activities will adjust themselves such that E is 0.

      We can calculate EH values for reactions not listed in Table 3.3 by algebraic combinations of the reactions and potentials that are listed. There is, however, a catch. Let's see how this works.

      Calculate the EH for the reaction:

equation

      Answer: This reaction is the algebraic sum of two reactions listed in Table 3.3:

equation equation

      We have neglected to take into consideration the number of electrons exchanged. In the algebraic combination of EH